Cum se aproximeaza radical de ordin 3 din 8,7 fara formula lui Taylor?
Inregistrati-va pentru a beneficia de cunostintele comunitatii, a pune intrebari sau a a raspunde la intrebarilor celorlalti.
Suntem o comunitate care incurajeaza educatia si in care se intalnesc know-how-ul si experienta cu perspective inovative de abordare a problemelor.
Autentificati-va pentru a pune intrebari, a raspunde la intrebarilor celorlalti sau pentru a va conecta cu prietenii.
V-ati uitat parola ? Introduceti adresa de email si veti primi o noua parola.
Please briefly explain why you feel this question should be reported.
Va rugam explicate, pe scurt, de ce credeti ca aceasta intrebare trebuie raportata.
Motivul pentru care raportezi utilizatorul.
2<∛8.7<∛9.261=2.1
2.01<∛8.7<2.09
2.02<∛8.7<2.08
2.03<∛8.7<2.07
2.04<∛8.7<2.06
2.05<∛8.7
2.051<∛8.7<2.059
………………………………….
2.056<∛8.7<2.057
Si asa mai departe ,pana la ce.
Zecimala doresti
multumesc! si daca vreau ln5 cum se procedeaza?
e~2.718283
1/(2^9)=0.000015256878906e^(1/2^9)=1.0019551
1/(2^8)=0.00390625e^(1/2^8)=1.003914
1/(2^7)=0.0078125..e^(1/2^7)=1.007843
1/(2^6)=0.15625..e^(1/2^6)=1.015748
1/(2^5)=0.03125..e^(1/2^5)=1.031744
1/(2^4)=0.0625/e^(1/2^4)=..1.0645
1/(2^3)=0.125../e^(1/2^3)=.1.1332
1/(2^2)=0.25.e^(1/2^2)=1.28403
½=0.5.e^ (1/2)= 1.648722
e^(25/16)=e^16/16*e^8/16*e^1/16=2.718283*1.648722*1.0645=4.771=e^400/256 .e^416/256=e^13/8=e(8/8)*e^4/8*e^1/8=2.718283.*1.648722*1.1332=5.0787 Deci
..
ln4.771lne^25/16=25/16=1.5625<ln5<ln5.0787=lne^26/16=26/16=1.625
.
e^404/256=e^101/64=e^64/64*e^32/64*e^(4+1)/64=2.718283.*1.648722*1.0645*1.015748=
4.8446
e^412/256=e^103/64=e*e^1/2*e^1/16*e^1/32*e^1/64=2.718283*1.648722*1.0645*1.031744*
1.015748==4.9992
Lne^404/256=ln4.8446=404/256=1.578<ln5>lne^412/256=ln4.9992
.
e^412/256=e^105472/65536=4.9992
e^105476/65536=e^26369/16384=e*e^1/2*e^1792/16384*e^1/16384=2.718283*1.648722*
1.0645*1.031744*1.015748*1.003914=5.01
Lne^412/256=ln4.9992=1.6094<ln5<lne^26369/16384=ln5.01=1.60943
Cred ca ajunge Daca nu ai inteles ceva intreaba
nu cred ca v-am cerut asa ceva!